squareroots and cuberoots Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Linear Equations
Squareroots & Cuberoots
$(3^2 × 4^2 × 5)$ ÷ 36 = $(?)^2$ – 80
Answer: (d)
$(?)^2$ = 80 + ${9 × 16 × 5}/36$ = 80 + 20 = 100
∵ ? = $√{100}$=10
$√{7 × 447 ÷ 21 + 73 - 26}$ = ?
Answer: (e)
? = $√{7× {447/21} + 73 - 26} = √{149 + 73 - 26} = √{196}$ = 14
The value of $√{388+√{127} + √{289}}$is
Answer: (c)
$√{388+√{127+√289}}$
= $√{388+√{127+√17}}$ [∵ $√289$ = 17]
= $√{388+√144}$ [∵ $√144$ = 12]
= $√{388+12}$=√400
= 20 [∵ $√400$ = 20]
If the square of a number is subtracted from 4052 and the difference is multiplied by 15, the answer so obtained is 41340. What is the number?
Answer: (b)
Let the number be x.
According to the question.
(4052 – $x^2$ ) × 15 = 41340
⇒4052 - $x^2 = {41340}/15=2756$
⇒$x^2$ = 4052 – 2756 = 1296
∴ $x = √1296$ = 36
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